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2021
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2021
Տնային առաջադրանք
categories: Հանրահաշիվ
- sin(π/2-α)=cosα
- tg(π/2-α)=ctgα
- cos(π/2-α)=sinα
- ctg(α-π)=ctgα
- tg(α-π)=tgα
- cos(3/2π-α)=-sinα
- sin(α-3/2π)=cosα
- cos(π+α)=-cosα
118
- sinα=210°=-1/2
- cosα=210°=-√3/2
- tgα=210°=√3/3
- ctgα=210°=√3
- sinα=5/4π=225°=-√2/2
- cosα=5/4π=225°=-√2/2
- tgα=5/4π=225°=1
- ctgα=5/4π=225°=1
- sinα=4/3π=240°=-√3/2
- cosα=4/3π=240°=-1/2
- tgα=4/3π=240°=√3
- ctgα=4/3π=240°=√3/3
119
- ctg(90°-α)=tgα
- cos(90°+α)=-sinα
- sin(270°-α)=-cosα
- sin(270°+α)=cosα
- tg(α-270°)=-ctgα
- ctg(α-180°)=ctgα
120
- cos(810°+α)=- sinα
- cos(990°-α)=- cosα
- tg(α-450°)=- ctgα
- tg(7π-α)=-tgα
121
- cos²(3π/2-x)=0+sin²(x)=sin²(x)
- tg²(π+x)=tg²π+tg²x=tg²x
- cos4(π-x)=-cos4(x)=cos4x
122
ա) sin²(180°-α)+sin²(270°-α)=sin²α+(-cos²α)=sin²α+cos²α=1
բ) sin(90°-α)+cos(180°+α)+tg(270°-α)+ctg(360°+α)=sin(90°-α)+cos(180°+α)-ctg α+ctg α=0
գ) sin(π+α)cos(π/2+α)-cos(2π+α)sin(3π/2-α)=-sin α×(-sin α)-cos α×(-cos α)=sin²α+cos²α=1
դ) tg α tg(π/2+α)tg(π+α)tg(3π/2+α)=tg α×(-ctg α)×tg α tg(3π/2+α)=-tgα × ctgα × tgα × (-ctg α)=tg α×1/tg α×tg α×1/tg α=1